A particle is projected from a point A with velocity u 
at an angle of 45º with horizontal as shown in figure. It strikes the plane BC at right angles. The velocity of the particle at the time of collision is:
A
B
C
D
u
Text Solution
Verified by ExpertsThe correct answer is:
C
Let v be the velocity at the time of collision.
Then, u 
cos 45º = v sin 60º
(u 
) 
= 
v = 
u
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